(x^2-9)/(x^3+2x^2+9)=0

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Solution for (x^2-9)/(x^3+2x^2+9)=0 equation: 


D( x )

x^3+2*x^2+9 = 0

x^3+2*x^2+9 = 0

x^3+2*x^2+9 = 0

x^3+2*x^2+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

x^3+2*x^2+9 = 12

1

-1

x = -1

x^3+2*x^2+9 = 10

-1

3

x = 3

x^3+2*x^2+9 = 54

3

-3

x = -3

x^3+2*x^2+9 = 0

-3

x+3

x^2-x+3

x^3+2*x^2+9

x+3

-x^3-3*x^2

9-x^2

x^2+3*x

3*x+9

-3*x-9

0

x^2-x+3 = 0

DELTA = (-1)^2-(1*3*4)

DELTA = -11

DELTA < 0

x in { -3} 

x in (-oo:-3) U (-3:+oo)

(x^2-9)/(x^3+2*x^2+9) = 0

x^3+2*x^2+9 = 0

x^3+2*x^2+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

x^3+2*x^2+9 = 12

1

-1

x = -1

x^3+2*x^2+9 = 10

-1

3

x = 3

x^3+2*x^2+9 = 54

3

-3

x = -3

x^3+2*x^2+9 = 0

-3

x+3

x^2-x+3

x^3+2*x^2+9

x+3

-x^3-3*x^2

9-x^2

x^2+3*x

3*x+9

-3*x-9

0

x^2-x+3 = 0

DELTA = (-1)^2-(1*3*4)

DELTA = -11

DELTA < 0

x in { -3} 

x+3 = 0

(x^2-9)/(x+3) = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { -3} 

x = 3

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